sqlserver 合并列数据的实现

(资料图片)

sql server 递归查询树型结构某节点的所有上级节点，并且把这些所有上级节点多行拼接为一行，即合并列数据

with eps_root(pk_eps, pk_parent, eps_code, eps_name) as
(
    SELECT
         pk_eps, pk_parent, eps_code, eps_name
     FROM pm_eps
     where enablestate = 2
       and pk_eps = "1001A11000000003P62E"
    union all
    SELECT
        e.pk_eps, e.pk_parent, e.eps_code, e.eps_name
    FROM pm_eps e
          inner join eps_root r on e.pk_eps = r.pk_parent
    where e.enablestate = 2
)

select distinct 
	eps_code = stuff((select "/" + convert(nvarchar(500), eps_code) from (select distinct eps_code from eps_root) r1 for xml path("")), 1, 1, ""),
	--此次需要使用eps_code排序，不然中文的会错乱顺序
	eps_name = stuff((select "/" + eps_name from (select top 99.99 PERCENT eps_name from eps_root order by eps_code) r2 for xml path("")), 1, 1, "")
from eps_root

执行sql，如下图效果：

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